Page: 1 2

Wikipaedia blackout backup service (20)

SirOpenSource's profile

Replies

18 Jan 12, 2:00 PM
SirOpenSource
UK(E), 6 yrs

Betony wrote:

Can you also give me some important facts that someone has just made up in their bedroom please.

I just went into my bedroom and made up some facts.

1. Spiders do not like raspberry jam.

2. No matter how many times you glaze a window it still feels cold.

3. I made my bed this morning after getting up.

SOS

The Titter_Ye_Not group - for when you don't feel too serious.
Linuxware - The Linux user goup
I believe in equality for everyone, except reporters and photographers. - Mahatma Gandhi
www.Londonmunch.co.uk
Londonmunch@hotmail.com - Enquiries

18 Jan 12, 2:27 PM
TuvaOrBust
UK(LU), 5 mths

maid_irene wrote:
How do I calculate the spin on a K0 maeson after a 13Mev collision?

Hugs,

irene.

The kaon meson has zero spin :p

18 Jan 12, 6:16 PM
Betony
UK, 7 yrs

SirOpenSource wrote:

Betony wrote:

Can you also give me some important facts that someone has just made up in their bedroom please.

I just went into my bedroom and made up some facts.

1. Spiders do not like raspberry jam.

2. No matter how many times you glaze a window it still feels cold.

3. I made my bed this morning after getting up.

SOS

Thanks so much, am not missing Wikipedia at all now.

One syllable short of a full haiku

18 Jan 12, 6:35 PM
lush_london
UK(WC), 6 yrs

maid_irene wrote:
How do I calculate the spin on a K0 meson after a 13Mev collision?

Hugs,

irene.

You could try here http://www.askthephysicist.com/index.html

and thank me later?

18 Jan 12, 6:53 PM
maid_irene
UK(LN), 6 yrs

Actually, it is normally quoted as + or- 1, however at very high energies it's not so clear cut. Something to to with tumbling?

Hugs,

irene.

fellatrix wrote:

maid_irene wrote:
How do I calculate the spin on a K0 maeson after a 13Mev collision?

Hugs,

irene.

you could just hazard a guess cos its only going to be 0 or 1. Whats it colliding with?

"Service which is rendered without joy helps neither the servant or the served. But all other pleasures and possessions pale into nothingness before service that is rendered in a spirit of joy."
Mahatma Gandi

18 Jan 12, 7:04 PM
fellatrix
UK, 2 yrs

maid_irene wrote:
Actually, it is normally quoted as + or- 1, however at very high energies it's not so clear cut. Something to to with tumbling?

Hugs,

irene.

fellatrix wrote:

maid_irene wrote:
How do I calculate the spin on a K0 maeson after a 13Mev collision?

Hugs,

irene.

you could just hazard a guess cos its only going to be 0 or 1. Whats it colliding with?

Well wiki seems to think it's zero for a Ko meson

smartarse

18 Jan 12, 10:22 PM
TuvaOrBust
UK(LU), 5 mths

maid_irene wrote:
Actually, it is normally quoted as + or- 1, however at very high energies it's not so clear cut. Something to to with tumbling?

Hugs,

irene.

I'm not sure if you are being serious or not here, but just in case you are...

Spin is an intrinsic property of a particle - it does not vary with energy or anything else. The spin of a kaon is always zero. Before a collision, after a collision, it doesn't matter; as long as it is still a kaon, it still has a spin of zero.

I'm not sure what you mean by 'tumbling'? I can't help but wonder if you have the quantum number of spin confused with the everyday use of the word?

And the +1 and -1 has me wondering if you are thinking of parity?

19 Jan 12, 10:20 AM
Lazer_Fantastico
4 mths

maid_irene wrote:
How do I calculate the spin on a K0 maeson after a 13Mev collision?

Hugs,

irene.

You're best off putting it on the wool cycle, then allowing it to drip dry.

19 Jan 12, 10:21 AM
Lazer_Fantastico
4 mths

TheSilverFox wrote:

Betony wrote:
How do you lag pipes.

Starting to play one bar after the rest of the band normally works...

Hee hee hee!